SOLUTION: Given that the first term of an Arithmetical Progression is 7 and its 10th term is twice the second term. (a) calculate the 19th term.(b) sum of 28th terms (c) difference between t
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Question 1124153: Given that the first term of an Arithmetical Progression is 7 and its 10th term is twice the second term. (a) calculate the 19th term.(b) sum of 28th terms (c) difference between the 9th and 6th terms
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Given that the first term of an Arithmetical Progression is 7 and its 10th term is twice the second term. (a) calculate the 19th term.(b) sum of 28th terms (c) difference between the 9th and 6th term
a= 7
a10 = a+9d
2nd term
a2= a+d
a+9d= 2(a+d)
7+9d = 14+2d
7d =7
d=1
a19= a+18d
a19= 25
S28 = 28/2(2*7+27)
=14*41=574
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