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A contractor who does not meet the deadline on the construction of a building is fined $40,000 per day for each of the first ten days of extra time, and for each additional day thereafter the fine is increased by $8,000. If the contractor is fined $1,008,000, by how many extra days was the construction delayed?
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The increase after first ten days is ambiguous. Could be a sequence.
ADDITIONAL DAYS FINE
1 48000
2 54000
3 62000
4 70000
5 78000
6 86000 ------398000
7 94000
8 102000 -------594000
9 110000
The extra days, some unknown n, which lead up to fines of 608000 dollars.
Sum from 48000 to 8000(n-1) is $608000.
------summation formula;
Algebra steps lead to ,...
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The solution looks like days extra after the first ten.