SOLUTION: the sum and product of the three numbers in a Geometric progression are 28 and 512 respectively. what are the three numbers

Question 1112803: the sum and product of the three numbers in a Geometric progression are 28 and 512 respectively. what are the three numbers
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the sum and product of the three numbers in a Geometric progression are 28 and 512 respectively. what are the three numbers
-----
a, ar, ar^2
--------------------
a(1+r+r^2) = 28
(ar)^3 = 512
----
ar = cbrt(512) = 8
----------------------
If a = 1 ; r = 8 then product = (ar)^3 = 512 and sum = 1(1+8+64) # 28
-----------
If a = 2 ; r = 4 then product = 512 and sum = 2(1+4+16) = 84
If a = 4 ; r = 2 then product = 512 and sum 4(1+2+4) = 28
-----
Cheers,
Stan H.
------
---------

RELATED QUESTIONS
Pls Help me with this question urgently,thanks. Find the three numbers in a... (answered by Edwin McCravy)

The product and sum of three consecutive terms in a Geometric Progression are 3375 and 65 (answered by stanbon)

Find 3 numbers in the geometrical progression whose sum is 28 and whose product is... (answered by ikleyn)

Find three numbers in arithmetic progression whose sum and product are six and six... (answered by ikleyn)

The sum of 3 numbers in arithmetic progression is 39. If these numbers are increased by... (answered by rothauserc)

The first three terms of a geometric progression are k + 15,k and k - 12 respectively,... (answered by ikleyn)

the sum three consecutive terms of geometric progression is 26 and the product of them is (answered by stanbon)

find the first 3 terms of a geometric progression whose sum is 42 and whose product is... (answered by htmentor)