SOLUTION: What will be the sum of 3+7+11+15+19 ________ upto 80 terms

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Question 1103960: What will be the sum of 3+7+11+15+19 ________ upto 80 terms
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13215)   (Show Source): You can put this solution on YOUR website!


The first term is 3 and the common difference is 4; so the 80th term is 3+79*4 = 319.

Let's write the beginning and end of the series of numbers:
3+7+11+15+ ... +311+315+319

Because the terms in the sequence are equally spaced, the 80 terms in the sequence can be grouped into 40 pairs, each with the same sum:
(3+319), (7+315), (11+311), ....

So the sum of all 80 terms is the sum of 40 pairs, each with a sum of (3+319)=322. That means the sum of the 80 terms is 322*40 = 12880.

Answer by ikleyn(52914)   (Show Source): You can put this solution on YOUR website!
.
Arithmetic progression with the first term  = 3  and the common difference d = 4.


Use the general formula for the sum of the first n terms of an arithmetic progression


 =  = .


In your case it is   =  = 12880.

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There is a bunch of lessons on arithmetic progressions in this site:
    - Arithmetic progressions
    - The proofs of the formulas for arithmetic progressions
    - Problems on arithmetic progressions
    - Word problems on arithmetic progressions
    - Mathematical induction and arithmetic progressions
    - One characteristic property of arithmetic progressions
    - Solved problems on arithmetic progressions


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

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