SOLUTION: Please find the limit of the following sequence as n goes to infinity: {{{n/(n^2+1) +n/(n^2+4)+ n/(n^2+9)}}}+...+ {{{n/(n^2+(n-1)^2)+1/(2n)}}}. Thank you!

Algebra.Com
Question 1103595: Please find the limit of the following sequence as n goes to infinity:
+...+ .
Thank you!

Found 2 solutions by math_helper, robertb:
Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!
Sorry, not a closed form solution, but some values as n gets "large"…

Let = Partial sum n,




: : :

: : :

: : :

: : :

——————————
Values found using a Perl one-liner (if you have Perl installed, edit the value of $m to set the max value)

perl -e '$m=1000000; for($i=0, $s=0; $i<$m; $i++) { $s += $m/($m*$m+($i+1)*($i+1)); }; print "Sum = $s\n";'
Sum = 0.785397913397392

Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS

Help me find the limit of (1 + √2 + √3 +... + √(n-1) + √n)/n^(3/2) as n goes to... (answered by greenestamps,ikleyn)
I've been working through factoring polynomials and have solved the following as such;... (answered by stanbon)
Please help me find the limit of 1/(2n+1) + 1/(2n+2) + 1/(2n+3) + ... + 1/(3n) as n goes... (answered by ikleyn)
Dear math teacher, I am having difficulties with the following problem: 4 times nC2 (answered by Theo)
n!(n+2)=n!+(n+1)! (answered by LinnW)
Please help me find a limit of an=n^2(n!)/(n+2)! the second is... (answered by AnlytcPhil)
2+4+6+.....2n=n(n+1) (answered by ikleyn)
find the sum of following series:... (answered by Edwin McCravy)
Determine if the limit exists as n goes to infinity: {{{ 1/(n+1)+1/(n+2)}}} +...+... (answered by math_helper)