SOLUTION: Three consecutive terms of a geometric sequence are x - 3, 6 and x + 2.
Find the possible values of x.
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Question 1096825: Three consecutive terms of a geometric sequence are x - 3, 6 and x + 2.
Find the possible values of x.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
the ratios between adjacent products should be equal
6/(x-3)=(x+2)/6
cross multiply
x^2-x-6=36
x^2-x-42=0
(x-7)(x+6)=0
x=-6, 7 ANSWER
For -6, the series is -9,6,and -4, a ratio of -(2/3)
For 7, the series is 4,6,9 for a ratio of 2/3
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