.
= = 5 for the 3-rd term.
= = 80 for the 5-th term.
Take the ratio
= = 16 = = .
Thus you have an equation for "r": = 16, which has TWO solutions: r = 4 and/or r = -4.
So, the two possibilities for the 4-th term are
1) = = 5*4 = 20, and
2) = = 5*(-4) = -20.
Solved.
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On geometric progressions, see the lessons in this site
- Geometric progressions
- The proofs of the formulas for geometric progressions
- Problems on geometric progressions
- Word problems on geometric progressions
- One characteristic property of geometric progressions
- Solved problems on geometric progressions
- Fresh, sweet and crispy problem on arithmetic and geometric progressions
- Mathematical induction and geometric progressions
- Mathematical induction for sequences other than arithmetic or geometric
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Geometric progressions".