SOLUTION: List the first six terms of the sequence defined by bn= (2*4*6 �2n)/2^n.

SOLUTION: List the first six terms of the sequence defined by bn= (246 �2n)/2^n.

Question 1091272: List the first six terms of the sequence defined by bn= (2*4*6 �2n)/2^n.

Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
.
List the first six terms of the sequence defined by bn= (2*4*6 �2n)/2^n.
~~~~~~~~~~~~~~~~~~~~~

1-st term, n= 1:   =  =  = 1.

2-nd term, n= 2:   =  = 2.

3-nd term, n= 3:   =  = 6.

4-th term, n= 4:   =  = 24.


Can you complete the assignment from this point on your own ?

RELATED QUESTIONS
list the first six terms of the sequence defined by bn=2*4*6......2n / 2^n for n is... (answered by lynnlo)

list the first six terms of the sequence defined by bn=2*4*6......2n / 2^n for n is... (answered by lynnlo)

List the first five terms of the sequence defined by an = n^2/n! for n ≥... (answered by MathLover1)

Suppose that a sequence is defined as follows. a[1] = -1 , a[n] = -3a[n-1]+6 for n... (answered by ewatrrr,solver91311)

list the first four terms of the sequence defined by an = (n+1)!/2n for n is greater... (answered by stanbon)

List the first four terms of the sequence defined by an =(n + 1)!/2n for for n is greater (answered by stanbon)

Write the first four terms of the sequence defined by a[n] = 2n +... (answered by atif.muhammad)

If a sequence is defined recursively by f(1)= -2 and f(n-1) = 3(n-1)-4, then find the... (answered by ikleyn)

Find the first 5 terms of the sequence defined by a(subscript)n = (-1)^n... (answered by fractalier)