SOLUTION: g(1)=−19  g(n)=g(n−1)+6  Find the explicit formula for g(n).

Question 1089065: g(1)=−19

g(n)=g(n−1)+6

Find the explicit formula for g(n).
Answer by ikleyn(52806) (Show Source): You can put this solution on YOUR website!
.

Thus defined function g(n) represents/describes the arithmetic progression with the first term -19 and the common difference of 6.


Therefore, the general formula for n-th term is


g(n) = - 19 + 6*(n-1),   n = 1, 2, 3, . . . ,


or, which is the same,


g(n) = (-19 - 6) + 6n = 6n - 25,  n = 1, 2, 3, . . .

Solved.

On arithmetic progression, see the lessons
There is a bunch of lessons on arithmetic progressions in this site:
    - Arithmetic progressions
    - The proofs of the formulas for arithmetic progressions
    - Problems on arithmetic progressions
    - Word problems on arithmetic progressions
    - Mathematical induction and arithmetic progressions
    - One characteristic property of arithmetic progressions
    - Solved problems on arithmetic progressions

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".

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SOLUTION: g(1)=&#8722;19 &#8203; &#8203;g(n)=g(n&#8722;1)+6 &#8203;&#8203; Find the explicit formula for g(n).

SOLUTION: g(1)=−19 g(n)=g(n−1)+6 Find the explicit formula for g(n).