SOLUTION: without nesessary expanding find the term tha does not contain valiable x in the expansion of (3x^2-1/4x)^6

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Question 1080712: without nesessary expanding find the term tha does not contain valiable x in the expansion of (3x^2-1/4x)^6
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
I am assuming this is (3x^2-(1/4x))^6
The fourth term will raise x^2 to the 2 and (1/4x)^4. That will give x^4 in both the numerator and denominator.
The leading term is 10 (1-5-10-10-5-1 in expansion to 6th power)
10*(3x^2)^2*(1/4x)^4
=10*9x^4*(1/256x^4)=90/256, or 45/128.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

without nesessary expanding find the term tha does not contain valiable x in the expansion of (3x^2-1/4x)^6
Correct answer: , which is . 

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