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Sum the following term of progression to the last term, logx, logx^2 logx^3.... logx^120
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What are your terms ???
or ???
USE PARENTHESES.
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Comment from student: Log(x^120)
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My response: OK, now I can complete the solution.
log(x) + log(x^2) + log(x^3) + . . . . + log(x^120) =
= log(x) + 2*log(x) + 3*log(x) + . . . . + 120*log(x) =
= log(x)*(1 + 2 + 3 + . . . . + 120) = = 7260*log(x).
Solved.
About this sum, 1 + 2 + 3 + . . . . + 120, see the lessons
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".