SOLUTION: Please could be found the rule of such a sequence: 72, 12, 6, 4, 3, 2, 2 ? Please don't modify the given series. The similar problem with 79, 24, 12... is much easier. What mig

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Question 1062664: Please could be found the rule of such a sequence:
72, 12, 6, 4, 3, 2, 2 ?
Please don't modify the given series.
The similar problem with 79, 24, 12... is much easier.
What might be the next number?
Thanks in advance,
Vlad
Found 2 solutions by Edwin McCravy, Alan3354:
Answer by Edwin McCravy(20065)   (Show Source): You can put this solution on YOUR website!
 The recursion formula is:

 a(n) = a(n-3)/a(n-1) 

72, 24, 12, 6, 4, 3, 2, 2, 3/2, 4/3, 3/2

 a(4) =  a(1)/a(3) = 72÷12  = 6     
 a(5) =  a(2)/a(4) = 24÷6   = 4     
 a(6) =  a(3)/a(5) = 12÷4   = 3     
 a(7) =  a(4)/a(6) =  6÷3   = 2     
 a(8) =  a(5)/a(7) =  4÷2   = 2     
 a(9) =  a(6)/a(8) =  3÷2   = 3/2    
a(10) =  a(7)/a(9) =  2÷3/2 = 2×(2/3) = 4/3   
a(11) = a(8)/a(10) =  2÷4/3 = 2×(3/4) = 3/4 

The 9th term, a(9) = 3/2

Edwin
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
IOW, problems like this are a waste of time.
There is nothing to be learned from them.
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