SOLUTION: Given that four integers are consecutive terms of an arithmetic sequence with sum 24 and product 945, what is the biggest of these four integers?

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Question 1055828: Given that four integers are consecutive terms of an arithmetic sequence with sum 24 and product 945, what is the biggest of these four integers?
Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
Since it is about 4 integers, consider divisibility.
is the factorization for 945.
You notice that 3, 5, and 7 are factors of 945,
and the form an arithmetic sequence!
If those were 3 of the 4 factors whose product is 954,
The fourth factor would be
.
So, ,
and those 4 factors form an arithmetic sequence.
Of course, , , , and are another answer.

USING EQUATIONS:
= common difference of the arithmetic sequence.
= average (mean) and median of thev4 numbers.
Then, the numbers are
, , , and .
The product is








So,
EITHER, ---> ,
which gives you the two arithmetic sequences found before,
OR , which gives you
two arithmetic sequences of four (irrational) numbers,
asking up to 24, and with a product of 945.

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