SOLUTION: how do I find the sum of the sequence in this problem;
40+41+42+43+...137
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Question 1054237: how do I find the sum of the sequence in this problem;
40+41+42+43+...137
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
You can find the sum from 1-137 and then subtract the sum from 1-39. Then you will have the sum from 40-137.
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1+2+3+...+39+40+41+...+136+137
1+2+3+...+39
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.......................40+41+...+136+137
Answer by ikleyn(52794) (Show Source): You can put this solution on YOUR website!
.
how do I find the sum of the sequence in this problem;
40+41+42+43+...137
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Arithmetic progression.
The first term 40.
The common difference 1.
The number of terms = 137 - 39 = 98.
Apply the formula for the sum of an arithmetic progression.
S = = = use your calculator.
On arithmetic progressions see the lessons
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
- Word problems on arithmetic progressions
- Chocolate bars and arithmetic progressions
- Mathematical induction and arithmetic progressions
- One characteristic property of arithmetic progressions
- Solved problems on arithmetic progressions
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".
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