.
Let me reformulate the problem in this way:
x and y are real numbers such that |x| < 1 and |y|< 1.
Find the infinite sum
Solution
Let "S" be the infinite sum
S = .
Multiply S by (x-y). Then
S = .
Now notice that
= , (1)
= , (2)
= (3) (make yourself this calc . . . )
And so on . . .
So, I suppose (and I am almost sure) that each parenthesed term in the original sum, multiplied by (x-y) will give . (4)
//"The margins of this page are too narrow . . . "
Thus we have
S*(x-y) = - = (5)
Now apply the formula for the infinite sum of a geometric progression
= .
Simplify it and then cancel the factor (x-y) in both sides.
Finally, you will get
S = = 1 - .
Again, the key is the idea with the formulas (1), (2), (3), (4), (5).
Answer. S = = 1 - .