SOLUTION: Bag A contains 15 marbles of which 8 are red and the rest are black. Bag B contains 14 marbles of which 4 are red 3 are blue and the rest are black. A ball is drawn at random first

Question 1033663: Bag A contains 15 marbles of which 8 are red and the rest are black. Bag B contains 14 marbles of which 4 are red 3 are blue and the rest are black. A ball is drawn at random first from bad A, and second from bag B. If we make the random variable be black marbles (B) complete the following.
A) Create a tree diagram:
B) complete a probability table for the number of black marbles
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
===8/14 red===========6/14 black
4/7 red====3/7 black ===4/7 red=====3/7 black
Probability of both black marbles is (3/7)(3/7)=9/49
probability of one black marble is (8/14)(3/7)+(6/14)(4/7)=24/49
probability of zero black marbles is (8/14)(4/7)=16/49
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