SOLUTION: the number of terms in the following arithmetic sequence...
3a-5, a+1, 7-a,..., 109-35a
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Question 1033214: the number of terms in the following arithmetic sequence...
3a-5, a+1, 7-a,..., 109-35a
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3a-5, a+1, 7-a,..., 109-35a
first term = 3a-5
d= (a+1)-(3a-5) = -2a+6
tn = 109-35a
109-35a = (3a-5)+(n-1)(-2a+6)
n=20
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