SOLUTION: Jeremy has a bag of peanuts. He is going to share them so he counts them out. First he uses groups of 2, then groups of 3, 5 and 8, but each time there is 1 peanut left. How many a

Question 1030735: Jeremy has a bag of peanuts. He is going to share them so he counts them out. First he uses groups of 2, then groups of 3, 5 and 8, but each time there is 1 peanut left. How many are in the bag? Is there more than one answer?
Please give me some ideas to solve this problem. Thanks !

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2, then groups of 3, 5 and 8, but each time there is 1 peanut left.
The number of peanuts must be 1 more than the multiples of all the above
2*3*5*8 = 120
121 peanuts is one possibility
You can form groups if you have 1 more than any multiple of 120 which is the LCM

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