SOLUTION: Thanks for your help, Have no idea Determine the first 5 susesion terms of: Bn=(-2)^(n-1)

SOLUTION: Thanks for your help, Have no idea Determine the first 5 susesion terms of: Bn=(-2)^(n-1)

Algebra.Com

Question 1027441: Thanks for your help, Have no idea
Determine the first 5 susesion terms of:
Bn=(-2)^(n-1)
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
What you do is to substitute the numbers 1 thru 5 for n...like this...

and so on...
RELATED QUESTIONS
Determine the first 5 susesion terms of: Thanks for your help bn=(-2)^(n-1) (answered by fractalier)

Please help me solve this.. I did it but can solve it Determine the first 4 susesion... (answered by fractalier)

Please need help. Thanks all the tutors here. Determine the first 5 susesion terms of: (answered by stanbon)

Write the first four terms of the sequence aV1=-3, aVn=(-2)aVn-1;n=2,3,4 I have no idea... (answered by venugopalramana)

list the first six terms of the sequence defined by bn=2*4*6......2n / 2^n for n is... (answered by lynnlo)

list the first six terms of the sequence defined by bn=2*4*6......2n / 2^n for n is... (answered by lynnlo)

determine the value of n that sets 2n-1 equal to 1/2 of 2n? I have no idea where to start (answered by jim_thompson5910)

n(n2-1n)+n(n-1) trying to help my daughter, no idea how to solve this. the 2 is n... (answered by stanbon)

List the first six terms of the sequence defined by bn= (2*4*6 �2n)/2^n. (answered by ikleyn)