SOLUTION: find the three numbers in an arithmetic progression whose sum is 48 and the sum of their squares is 800

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Question 1017801: find the three numbers in an arithmetic progression whose sum is 48 and the sum of their squares is 800
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
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find the three numbers in an arithmetic progression whose sum is 48 and the sum of their squares is 800
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One can present the three consecutive terms of the AP as

x -d, x, x + d,

where x is the mid term and d is the common difference.

Then the sum of the tree terms is 3x, and you can easily find a from the equation

3x = 48,

which implies x =  = 16.

Now the sum of squares of the tree terms is

 =  =  = .

It gives you an equation to find d:

 =   --->   =  = 32  --->   =  = 16.

Hence, d = +/- 4.

It gives the AP terms as  12, 16 20,   or   20, 16, 12.

Answer. AP terms are  12, 16 20,   or   20, 16, 12.


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