SOLUTION: The fifth term of an arithmetic sequence is 23 and the 12th term is 72.
1.1determine the first three term of the sequence and the nth term.
1.2what is the value of the tenth term
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Question 1015486: The fifth term of an arithmetic sequence is 23 and the 12th term is 72.
1.1determine the first three term of the sequence and the nth term.
1.2what is the value of the tenth term?
1.3which term is equal to 268?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
a5+a4+d
23=a1+4d
72=a1+11d
a1=23-4d=72-11d
49=7d;d=7
If a5=23. a1=-5,a2=2,a3=9, and an=-5+(7(n-1)) ANSWER A.
a10=-5+9*7=58 ANSWER B.
268=-5+7(n-1)
273=7n-7
280=7n; n=40th term.ANSWER C.
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