SOLUTION: 1.given that three numbers form an A.P.their sum is 21,and their product is 231.find these numbers.
Algebra.Com
Question 1006280: 1.given that three numbers form an A.P.their sum is 21,and their product is 231.find these numbers.
Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
1. Given that three numbers form an A.P. Their sum is 21,and their product is 231.find these numbers.
-------------------------------------------------------------------
Let x be the middle term of this A.P.
Then the three terms are (x-d), x and (x+d).
The sum of three is 3x = 21. Hence, x = 7.
The product of three is (7-d)*7*(7+d) = 231, or
49-d^2 = = 33.
Hence, d^2 = 49 - 33 = 16, and d = 4.
The three numbers are 7-4 = 3, 7, and 7+4 = 11.
RELATED QUESTIONS
Find three numbers in GP such that their sum is 39 and their product is... (answered by Alan3354,greenestamps)
Find the three numbers in an AP such that their sum is 27 and their product is... (answered by ikleyn)
The sum of 3 numbers in an A.P is 21 and their product is 280. find the numbers
(answered by mananth)
The sum of two numbers is thirteen and their product is 21. Find the two... (answered by checkley79)
the sum of 3 numbers is 21 and their product is 280. find the... (answered by richwmiller)
the sum of 3 numbers is 21 and their product is 280 find the numbers
(answered by richwmiller)
find two positive numbers such that their sum is 25 and their product is a... (answered by chriswen)
The sum of three numbers in an arithmetic sequence is 9 and their product is 24. Find... (answered by Alan3354)
two numbers is a product that is 35 more than their sum. what are these... (answered by ankor@dixie-net.com)