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Tutors Answer Your Questions about Rectangles (FREE)
Question 149659: A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position? This comes from the THEA Practice Test. Thanks
Click here to see answer by nerdybill(2448)  |
Question 151539: Can you help me with this problem. The lenght of a rectangular garden is 20 feet longer than the width. The perimeter must be between 80 and 100feet for the fencing that has been purchased. What are the possible widths for the garden.
I started with p=2L=2W Perimeter
A=LW
I don't where to even start.
Click here to see answer by jim_thompson5910(13794)  |
Question 152104This question is from textbook
: Okay here is a tough one, for me anyway. I would appreciate some help with this problem:
You have a sheet of 8.5 x 11 inch paper. You need to measure exactly six inches. You don't have a ruler or other measuring device. Can you measure exactly six inches using the sheet of paper? Explain.
Thanks to any and all who help.This question is from textbook
Click here to see answer by Earlsdon(4900)  |
Question 152104This question is from textbook
: Okay here is a tough one, for me anyway. I would appreciate some help with this problem:
You have a sheet of 8.5 x 11 inch paper. You need to measure exactly six inches. You don't have a ruler or other measuring device. Can you measure exactly six inches using the sheet of paper? Explain.
Thanks to any and all who help.This question is from textbook
Click here to see answer by scott8148(3385)  |
Question 152281This question is from textbook 
: You have 480 feet of fencing to enclose a rectangular garden. You want the length of the garden to be 30 feet greater than the width. Find the length and width of the garden. How long should each piece be?This question is from textbook 
Click here to see answer by ankor@dixie-net.com(6693)  |
Question 154586: The width of a rectangular box is 4 times its height, and its length is 3 ft more than its height. The volume of the box is 49 ft cube. Find the height of the box.
volume = lwh
49 = (4x)(3+x)(x)
49 = 4x3 +12x2
Click here to see answer by stanbon(26296)  |
Question 156656: A box with an open top is to be constructed from a rectangular piece of cardboard with dimensions 15 inches by 30 inches by cutting out equal squares of side x at each corner and then folding up the sides
So I have to find the volume when l=30-2x, w=15-2x and h=x
I tried to multiply everything out and got 4x^3-60x^2+450x... but got stuck... not sure wether doing that was right and if so how to continue - looked at taking x out, but still ended up in a big mess - could someone do a step by step breakdown please?
Click here to see answer by scott8148(3385)  |
Question 158677: I will first describe the picture. There is a rectangle, ABCD with the long side labeled y and short side labeled x.
Here is the question.
If the perimeter of the rectangle ABCD is equal to p, and x=1/5 y, what is the value of y in terms of p?
I know the answer is (5p)/(12) but am not sure how this answer is derived?
Any ideas?
Thanks!
Click here to see answer by edjones(3298)  |
Question 159212: A rectangular patio is surrounded on three sides by a fence (the remaning side is up against the house). If the area of the patio is 38 meter square, and the total length of fence is 18 meters, what is the length and width of the patio.
Click here to see answer by KnightOwlTutor(292)  |
Question 159212: A rectangular patio is surrounded on three sides by a fence (the remaning side is up against the house). If the area of the patio is 38 meter square, and the total length of fence is 18 meters, what is the length and width of the patio.
Click here to see answer by Alan3354(6096)  |
Question 159212: A rectangular patio is surrounded on three sides by a fence (the remaning side is up against the house). If the area of the patio is 38 meter square, and the total length of fence is 18 meters, what is the length and width of the patio.
Click here to see answer by gonzo(654)  |
Question 160339: The area of a rectangle is 30 cm^2. The perimeter is 26cm. What are the length and width of the rectangle.
this is what i have so far
a=lw so 30= lw
p=2L + 2W so 26= 2L+2W
I'm not sure if I am supposed to substitute the first equation into the second one or just try to isolate L and w.
thanks.
Click here to see answer by checkley77(7072)  |
Question 160339: The area of a rectangle is 30 cm^2. The perimeter is 26cm. What are the length and width of the rectangle.
this is what i have so far
a=lw so 30= lw
p=2L + 2W so 26= 2L+2W
I'm not sure if I am supposed to substitute the first equation into the second one or just try to isolate L and w.
thanks.
Click here to see answer by Electrified_Levi(103)  |
Question 162778: As a real estate tycoon you have bought a rectangular parcel of waterfront property and want to enclose your land as follows: Using 5000 feet of fencing you want to enclose a rectangular section on only three sides using the water as the 4th side. What dimensions (length and width of the rectangle) should the enclosure be to assure maximum area?
I have been working on this problem for over two hours, it's ripping my mind apart! PLEASE HELP.
Click here to see answer by checkley77(7072)  |
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