SOLUTION: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions.
Algebra.Com
Question 993576: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions.
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Make the width = 'x'
Length = 2x - 17
Perimeter = 2 x Width + 2 x Length
203 = 2(x) + 2(2x - 17)
203 = 2x + 4x - 34
collect like terms.
2x + 4x = 203 + 34
6x = 237
x = 237/6
x = 39.5 meters
Width = 39.5 meters
Length = 62 meters
Hope this helps :-)
RELATED QUESTIONS
the length of a rectangle is 75 meters less than twice the width the perimeter is 600... (answered by ikleyn)
The perimeter of a rectangle is 76 meters. the length is 16 meters less than twice the... (answered by praseenakos@yahoo.com)
the length of a rectangle is 7 meters less than twice he width. If the perimeter is 40... (answered by mananth)
The width of a rectangle is 3 meters less than the length. The perimeter is 14 meters.... (answered by Earlsdon)
the width of a rectangle is 3 meters less than the length. the perimeter is 14 meters.... (answered by user_dude2008)
the length of a rectangle parking lot is 10 meters less than twice the width, the... (answered by mananth)
the length of a rectangle is 4 meters less than 3 times the width. If the perimeter is 56 (answered by oberobic)
the length of a rectangle is 4 meters less than 3 times the width. If the perimeter is 48 (answered by josgarithmetic)
the width of a rectangle is 5 meters less than is length, and the perimeter is 26 meters. (answered by JulietG)