SOLUTION: The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 23 cm^2, what is the length of the diagonal?
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Question 987645: The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 23 cm^2, what is the length of the diagonal?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 23 cm^2, what is the length of the diagonal?
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Length:: x
Width:: 2x-5
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x(2x-5) = 23
2x^2 -5x - 23 = 0
x = 4.86
2x-5 = 4.72
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Ans: diag = sqrt(4.86^2+4.72^2) = 6.77 cm
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Cheers,
Stan H.
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