SOLUTION: how do i find the diagnol length of the rhombus which is inscribed in rectangle whose length is 16 cms and breadth is 12 cms.

Question 983977: how do i find the diagnol length of the rhombus which is inscribed in rectangle whose length is 16 cms and breadth is 12 cms.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Here is my solution (EF = 15) to your problem using the diagram you sent me

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from snap shot rhombus AEDF gives us line segments AF, ED, AE, FD are
the same length
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AE^2 = CE^2 + AC^2 or
FD^2 = (16-FD)^2 + 12^2
FD^2 = 256 + FD^2 - 32FD + 244
32FD = 400
FD = 400 / 32 = 12.5
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area of rhombus(A) = FD * BD = 12.5 * 12 = 150
note that BD is height of rhombus
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also A = (1/2) * EF * AD
note AD^2 = AB^2 + BD^2 = 16^2 + 12^2 = 256 + 144 = 400
AD = square root(400) = 20
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(1/2) * EF * 20 = 150
10 * EF = 150
EF = 15
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