SOLUTION: Suppose the length of a certain rectangle is 7 meters more than twice its width and the perimeter is 50 meters. The width must be ??? meters.

Question 964145: Suppose the length of a certain rectangle is 7 meters more than twice its width and the perimeter is 50 meters.
The width must be ??? meters.
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
2L+2W= 50 and the problem says that L= 2W+7, so we substitute for L:
2(2W+7)+2W= 50 Multiply on left:
4W+14+2W= 50 Subtract 14 on both sides and add W on left:
6W= 36 Divide both sides by 6:
W= 6 This is the width
And the length? The problem doesn't ask for it, but it doesn't hurt for you to have it. It's 6*2+7= 19
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