SOLUTION: The length of a rectangle garden is 2 less than 3 times the width. If the area is 341in. find the length, width, and perimeter of the rectangle.

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Question 956294: The length of a rectangle garden is 2 less than 3 times the width. If the area is 341in. find the length, width, and perimeter of the rectangle.
Answer by amarjeeth123(569)   (Show Source): You can put this solution on YOUR website!
Let the width be x.
Then the length is 3x-2
Area=341=length*width
x(3x-2)=341
3x^2-2x-341=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=4096 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 11, -10.3333333333333. Here's your graph:

x=11
The width of the rectangle is 11 inches.
The length of the rectangle is 31 inches.
Perimeter=2(11+31)=84 inches.
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