SOLUTION: a square has the same area as a rectangle whose length is 8 feet more than the side of the square and whose width is 4 feet less than the side of the square.find the side of the sq

Question 956007: a square has the same area as a rectangle whose length is 8 feet more than the side of the square and whose width is 4 feet less than the side of the square.find the side of the square , i really dont know how to solve it with out the given area

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
We are given
area of square = area of rectangle
let s be the side of the square, then
s^2 = (s+8)*(s-4)
s^2 = s^2 +4s -32
subtract s^2 from both sides of =
0 = 4s -32
add 32 to both sides of =
4s = 32
s = 8
The length of a side of the square is 8 feet
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