SOLUTION: If rectangle ABCD has an area of 10 square inches and a perimeter of 22 inches. What is the length and width?

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Question 950064: If rectangle ABCD has an area of 10 square inches and a perimeter of 22 inches. What is the length and width?
Found 2 solutions by Fombitz, lwsshak3:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Area:
L%2AW=10
Perimeter:
2L%2B2W=22
L%2BW=11
Substitute from first equation,
10%2FW%2BW=11
10%2BW%5E2=11W
W%5E2-11W%2B10=0
%28W-10%29%28W-1%29%29%29=0
Two solutions,
W-10=0
W=10
Then,
L%2B10=11
L=1
and
W-1=0
W=1
Then,
L%2B1=11
L=10

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
If rectangle ABCD has an area of 10 square inches and a perimeter of 22 inches. What is the length and width?
***
let x=width
let y=length
..
2x+2y=perimeter=22
x*y=area=10
y=10/x
2x+2y=2x+2(10/x)=22
2x+20/x=22
lcd:x
2x^2+20=22x
x^2-11x+10=0
(x-10)(x-1)=0
x=1
y=10/x=10
width=1 inch
length=10 inches