SOLUTION: The length of a rectangle is 3 ft less than twice the width, and the area of the rectangle is 14 ft squared . Find the dimensions of the rectangle.

Algebra.Com
Question 947820: The length of a rectangle is 3 ft less than twice the width, and the area of the rectangle is 14 ft squared . Find the dimensions of the rectangle.
Answer by amarjeeth123(569)   (Show Source): You can put this solution on YOUR website!
Let the width be x ft.
Then the length is (2x-3) ft.
Area of the rectangle=x(2x-3)
x(2x-3)=14
2x^2-3x-14=0
2x^2-7x+4x-14=0
x(2x-7)+2(2x-7)=0
(2x-7)(x+2)=0
x=7/2=3.5 feet.
The width is 3.5 feet and the length is 4 feet.

RELATED QUESTIONS

the area of a rectangle is 77 ft. squared and the length is 3 ft more than twice the... (answered by josgarithmetic)
The area of a rectangle is 42 ft. squared, , and the length of the rectangle is 11 ft.... (answered by stanbon)
The length of a rectangle is 3 ft less than double the width, and the area of the... (answered by josgarithmetic)
The length of a rectangle is 6 ft less than twice the width. The area of the rectangle is (answered by josgarithmetic)
The length of a rectangle is 3 ft less than twice it's width. If the perimeter of... (answered by addingup)
The length of a rectangle is 3 ft less than double the width, and the area of the... (answered by fractalier)
The perimeter of a rectangle is 42 ft. The length of the rectangle 3 ft. less than twice... (answered by richard1234)
The length of a rectangle is 5 ft less than double the width, and the area of the... (answered by TimothyLamb)
the length of a rectangle is 5 ft more than twice its width, and the area of the... (answered by rapaljer)