SOLUTION: If the area of a rectangle is x2 + 7x + 12 square meters and the length and width of a second rectangle are 3 meters longer, what is the area of the second rectangle?

Question 943104: If the area of a rectangle is x2 + 7x + 12 square meters and the length and width of a second rectangle are 3 meters longer, what is the area of the second rectangle?

Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Not enough info.

For example, the length could be 1 and the width could be x^2 + 7x + 12. Then the new length and width are 4 and x^2 + 7x + 15, respectively, and the new area is 4x^2 + 28x + 60.

Or, perhaps, the length and width are x+3 and x+4, and the new length and width are x+6 and x+7, and the new area is (x+6)(x+7) = x^2 + 13x + 42.

Or we could generalize this and say that the length is L and the width is (x^2 + 7x + 12)/L, then add 3 to length/width and multiply.

The problem is likely an exercise in factoring the quadratic into (x+3)(x+4), but you cannot claim that the dimensions are x+3 and x+4, and it is a poor-quality problem.
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