SOLUTION: The length of a rectangle is 2 m more that the width. The area is 48 m2. Find the dimensions of the rectangle.

Question 939578: The length of a rectangle is 2 m more that the width. The area is 48 m2. Find the dimensions of the
rectangle.

Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
let width be x meters
length = 2+x
area = 48 m^2
formula: area = length x width
48 = (2+x)*x
48= 2*x+x*x

move 48 to the right

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=196 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6, -8. Here's your graph:

x cannot be negative
hence x= 6
width (x)= 6 m
length = 6+2 = 8 m
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