SOLUTION: The width of a rectangular picture is 8in less than the length. The area of the picture is 20in^2. what are the dimensions of the picture?

Question 939572: The width of a rectangular picture is 8in less than the length. The area of the picture is 20in^2. what are the dimensions of the picture?

Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
let length be x in
width = x-8
area = 20 in^2
formula: area = length x width
20 = x*(x-8)
20 = x*x-x*8

move 20 to the right

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=144 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 10, -2. Here's your graph:

but x cannot be negative .
it should be positive value
x=10
length = 10 in
width = 10-8 = 2 inches
Result: length = 10 in
width = 2 in
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