SOLUTION: the perimeter of s rectangle is 58, the length is 5 more then the width what are the dimensions

Question 934656: the perimeter of s rectangle is 58, the length is 5 more then the width what are the dimensions
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
2L + 2w = 58
L = w + 5
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2L + 2w = 58
2(w + 5) + 2w = 58
2w + 10 + 2w = 58
4w = 48
w = 12
L = 17
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