SOLUTION: The length of a rectangle is 5 ft less than double the width, and the area of the rectangle is 33 ft 2. Find the dimensions of the rectangle.

Question 928566: The length of a rectangle is 5 ft less than double the width, and the area of the rectangle is 33 ft 2. Find the dimensions of the rectangle.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
Lw = 32
L = 2w - 5
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Lw = 32
(2w - 5)w = 32
2ww - 5w - 32 = 0
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the above quadratic equation is in standard form, with a=2, b=-5 and c=-32
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
2 -5 -32
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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w = 5.44076365
w = -2.94076365
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the negative root doesn't fit the problem statement, so use the positive root:
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w = 5.44076365
L = 2w - 5
L = 2*5.44076365 - 5
L = 5.8815273
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answer:
w = 5.44076365 ft
L = 5.8815273 ft
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