SOLUTION: How would I solve the dimensions of a rectangle if the length is 3cm more than the width and the diagonal is 15cm? I'm supposed to use factored form for the problem but I haven'

Question 925562: How would I solve the dimensions of a rectangle if the length is 3cm more than the width and the diagonal is 15cm?
I'm supposed to use factored form for the problem but I haven't been able to solve it. I know it has something to do with isolating w.
So far, I've subbed in w + 3 for the length and tried pythagorean theorem. But that answers keep coming up wrong. They should be 12 by 9.
Found 2 solutions by josgarithmetic, srinivas.g:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
w for width, L for length, d for the size of the diagonal.

A rectangle with dimensions L and w and diagonal d forms two right triangles allowing for the Pythagorean Theorem arithmetic statement .

According to your example description, L=w+3 and d=15.
;
take this the rest of the way.

(You should find along the way, .)
Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
Let width be w cm
length = (w+3) cm
diagonal = 15 cm
as per pythagorean theorem

move 225 to the right

on dividing with 2 both sides

(w-9) =0 or (w+12 )= 0
w=9 or w=-12
w cannot be negative
so w= 9
l = w+3 = 12
so length = 12 cm
width = 9 cm

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