SOLUTION: The length of a rectangle is 10cm more than its width if the area is 80cm^2 calculate it's perimeter

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Question 918902: The length of a rectangle is 10cm more than its width if the area is 80cm^2 calculate it's perimeter
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
.
A = (w+10)w = 80cm^2
w^2 + 10w - 80 = 0
(Tossing out the negative solution for unit measure)
w = 5.247 (rounded) and L = 15.247
P = 2(20.247) cm = 40.247
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=420 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 5.2469507659596, -15.2469507659596. Here's your graph:

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