SOLUTION: A rectangle is drawn so that the width is 4 feet shorter than the length. The area of the rectangle is 12 square feet. Find the length of the rectangle.

Algebra.Com
Question 918182: A rectangle is drawn so that the width is 4 feet shorter than the length. The area of the rectangle is 12 square feet. Find the length of the rectangle.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
.
L(L-4) = 12ft^2
L^2 - 4L - 12 = 0 (Tossing out the negative solution for unit measure)
(L+2)(L-6) = 0
L = 6ft
And...checking
(6ft)(2ft) = 12ft^2
RELATED QUESTIONS

A rectangle is drawn so that the width is 4 feet shorter than the length. The area of the (answered by ben720,josgarithmetic)
A rectangle is drawn so that the width is 1 feet shorter than the length. The area of the (answered by Alan3354)
A rectangle is drawn so that the width is 4 feet shorter than the length. The area of the (answered by Boreal)
A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the (answered by Fombitz)
A rectangle is drawn so that the width is 5 feet shorter than the length. The area of the (answered by Fombitz)
A rectangle is drawn so that the width is 5 feet shorter than the length. The area of the (answered by Cromlix)
A rectangle is drawn so that the width is 3 feet shorter than the length. The area of the (answered by ikleyn)
A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the (answered by Theo)
a rectangle has a width 5 feet shorter than the length. the area of the rectangle is 14... (answered by algebrahouse.com,ewatrrr)