SOLUTION: The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle?

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Question 914040: The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle?
Found 2 solutions by Lenzky, MathTherapy:
Answer by Lenzky(18)   (Show Source): You can put this solution on YOUR website!
- Length
- Wide
Perimeter

Area


times both side by 4




&
Checking:
Length:
Wide:
P= 2L + 2W
P= 2(20) + 2(5)
P= 40 + 10
P= 50
A= LW
A= 20 x 5
A= 100
2P = A
2(50) = 100
100 = 100

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle?

Let width of rectangle be W
Then length = 4W
Area of rectangle: W(4W), or
Perimeter of rectangle: 2(W + 4W), or 2(5W), or 10W
Therefore, we get:


4W(W – 5) = 0
W – 5 = 0 OR 4W = 0
W, or width = OR W = 0 (ignore)
Length: 4(5), or units of length
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