SOLUTION: The length of a lacrosse field is 15 yards less than twice its width, and the perimeter is 330 yards. The defensive area of the field is 5/21 of the total field area. Find the defe
Question 911226: The length of a lacrosse field is 15 yards less than twice its width, and the perimeter is 330 yards. The defensive area of the field is 5/21 of the total field area. Find the defensive area of the lacrosse field. Found 2 solutions by ewatrrr, ichigo449:Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi, .
L + w = 165
(2w-15) + w = 165
3w = 180
w = 60yd and L = 105yd
A = = 1500yd^2
Answer by ichigo449(30) (Show Source): You can put this solution on YOUR website! Let x be the length of the field and y the width. The first condition in the question says that x= 2y-15. Then the perimeter gives us a linear equation:
2y + 2(2y-15) = 330
This can be simplified to 6y-30 = 330 or 6y = 300 so y = 60. Then, by x = 2y-15, x = 105. Now from area of a rectangle, x*y, we get the total field area to be: 6300. Since the defensive area is 5/21 the total area we conclude that it must be 1500 yards square.
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