SOLUTION: the perimeter of a rectangle is 76 feet. find the dimensions assuming that its length is 4 feet less than 2 times its width
Algebra
.Com
Question 908516
:
the perimeter of a rectangle is 76 feet. find the dimensions assuming that its length is 4 feet less than 2 times its width
Answer by
ewatrrr(24785)
(
Show Source
): You can
put this solution on YOUR website!
Hi,
.
L + w = 38ft
(2w-4) + w = 38ft
3w = 42ft
w = 14ft and L = 24ft
and....
L + w = 38ft
RELATED QUESTIONS
The length of a rectangle road sign is 2 feet less than three times its width. Find the...
(answered by
satyareddy22
)
the length of a rectangle is 3 feet less than five times its width. the perimeter is 66...
(answered by
ptaylor
)
Algebra 2 word problem: The width of the rectangle is 3 feet less than its length. The...
(answered by
stanbon
)
The length of a banquet table is 3 feet longer than 4 times its width. If the perimeter...
(answered by
ewatrrr
)
The width of a rectangle is 3 feet less than its length. The Perimeter of a rectangle is...
(answered by
JulietG
)
the width of a rectangle is 2 inches more than 3 times its length. if the perimeter of...
(answered by
ewatrrr
)
the perimeter of a rectangle garden is 76 ft. the length is six feet less than three...
(answered by
Mathtut
)
The length of a rectangle is 9 feet more than its width. The perimeter is 58 feet. find...
(answered by
ewatrrr
)
The length of a rectangle is 3 feet less than twice its width. If the perimeter is 54...
(answered by
waynest
)