SOLUTION: I am trying to figure out this problem!!! It is "The length of a rectangle is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width. Find the

Question 907989: I am trying to figure out this problem!!! It is
"The length of a rectangle is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width. Find the length and width of the rectangle."
i have already tried X=4+(3w)+(w+22) but I don't know if it is right, or has been formatted correctly.
Thank You for your Time,
Mr_Bunston
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

     .

2(3w-4) + 2w = 2w+22

6w - 8 + 2w = 2w + 22

6w = 30

w = 5 units and L = 11 units

checking...

32 = 10 + 22 

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