SOLUTION: The length of the rectangle is 11 less than twice its width. If the perimeter is 86 what is the length and width of the rectangle?

Question 905658: The length of the rectangle is 11 less than twice its width. If the perimeter is 86 what is the length and width of the rectangle?
Answer by rm29924(97) (Show Source): You can put this solution on YOUR website!
Let X = the width
the length is 11 less than twice the width so
Length = 2x-11
the perimeter of a rectangle = 2W + 2L so
2X + 2(2X-11) = 86
2X + 4X -22 = 86
add 22 to both sides
2X + 4X = 108
6X = 108
divide both sides by 6
X = 18
check the answer
2(18) + 2(2(18)-11) = 86
36 + 2(36-11) = 86
36 + 2(25) = 86
36 + 50 = 86
86 = 86

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