SOLUTION: Find the dimensions of a rectangle if the perimeter is 14in and the area is 12cm square

Question 894754: Find the dimensions of a rectangle if the perimeter is 14in and the area is 12cm square
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the dimensions of a rectangle if the perimeter is 14in and the area is 12cm square
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P = 14 in = 14*2.54 cm
P = 35.56 cm
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P = 2W + 2L = 34.56
L + W = 17.28 --> L = 17.28 - W
L*W = 12
W*(17.28 - W) = 12
W^2 - 17.28W + 12 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=250.5984 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 16.5551500301637, 0.724849969836327. Here's your graph:

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W = 1 solution
L = the other
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