SOLUTION: the length of a rectangle is 3 feet less than twice the width. If the area of the rectangle is 54 ft^2, find the dimensions of the rectangle. Solve by using a quadratic equation

Question 891321: the length of a rectangle is 3 feet less than twice the width. If the area of the rectangle is 54 ft^2, find the dimensions of the rectangle. Solve by using a quadratic equation

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
w with
L length
L=-3+2w and wL=54

Factorable? 54=27*2=3*3*3*2=9*6

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Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

the length of a rectangle is 3 feet less than twice the width. If the area of the rectangle is 54 ft^2, find the dimensions of the rectangle. Solve by using a quadratic equation

Width: ft
Length: ft
You can do the check!!
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