SOLUTION: please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.

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Question 890730: please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
VARIABLES: w for width, L for length


TRANSLATE: L=-8+3w, 2w+2L=64.

SIMPLIFY AND SUBSTITUTE:
w+L=32;
w+(3w-8)=32

SOLVE FOR w FIRST:
4w-8=32
4w=24
w=6

Finish finding L:
L=3w-8
L=3*6-8
L=18-8
L=10

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.

Width: m
Length: m
You can do the check!!
If you need a complete and detailed solution, let me know!!
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