SOLUTION: a poster is designed so that its length will always be 4 inches more than its height. The height is x inches. The area of the poster (length times height) is y square inches. Write

Algebra.Com
Question 885562: a poster is designed so that its length will always be 4 inches more than its height. The height is x inches. The area of the poster (length times height) is y square inches. Write an equation that best describes the word problem above
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Assign variables to everything you can unless already assigned in the description and write the numeric facts that the description indicates.

x = height
y = area
u = length (could be any other variable not yet assigned)
-
u=4+x

The description can give you a relationship for all of these using formula for area: ;

Area, , or , or if you want to solve the length equation for x, you can show y as a function of u.

RELATED QUESTIONS

The length of a rectangular poster is 3 inches more than three times its width. Find the... (answered by macston)
A rectangular poster has an area of 190 inches squared the height of a poster is one inch (answered by JulietG)
A poster has a triangular image with a base that measures 4 inches, and a height that... (answered by MathLover1)
the base of a rectangle is 7 inches more than its height. if the area of the rectangle is (answered by richwmiller)
A triangular poster is twice as long as its height. A rectangular banner is 3 inches... (answered by Fombitz)
A poster has a length 4 inches greather than its width w. Demetrius will place a frame 2... (answered by Earlsdon)
A Standard rectangular shipping box has a length which is 3.5 inches more than its... (answered by greenestamps)
The length of a rectangular poster is 2 times its width . The area of the poster is 648... (answered by TimothyLamb)
The diagonal of a television set is 52 inches long. Its length is 28 inches more than its (answered by user_dude2008,checkley77,oberobic)