SOLUTION: The length of a rectangle is 7in more than twice the width. The perimeter is 68 inches. Find the length and the width.
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Question 884347: The length of a rectangle is 7in more than twice the width. The perimeter is 68 inches. Find the length and the width.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
L length
w width
L=7+2w and 2w+2L=68.
SUBSTITUTE!
2w+2(2w+7)=68
w+2w+7=34
3w=34-7
3w=27
w=9
.
.
L=2w+7
L=2*9+7
L=18+7
L=25
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