SOLUTION: The length of rectangle is three times its width, with a perimeter of 80 cm, solve for the rectangles area.

Algebra.Com
Question 883096: The length of rectangle is three times its width, with a perimeter of 80 cm, solve for the rectangles area.
Answer by JulietG(1812)   (Show Source): You can put this solution on YOUR website!
2L + 2W = P
2L + 2W = 80
L = 3W
Substitute the known value of L from the last equation into the first.
2(3W) + 2W = 80
6W + 2W = 80
8W = 80
Divide each side by 8
W = 10
.
If the width is 10, then the length is 3x that, or 30
Area = length * width
A = 10 * 30
Area = 300 square cm

RELATED QUESTIONS

the length of a rectangle is three times its width. If the area of the rectangle is 75... (answered by josmiceli)
The length of a rectangle is three times its width. If the area of the rectangle is 192... (answered by nerdybill)
The length of a rectangle is three times its width. If the area of the rectangle is 300 (answered by JulietG)
The rectangle shown has a perimeter of 46 cm and the area as 76 cm^2. Its length is 7... (answered by Alan3354)
a rectangles length is 9 times its width. If the perimeter if the rectangle is 60 cm,... (answered by checkley77)
The length of a rectangle is three times its width. If the area of the rectangle is ,... (answered by richard1234)
The length of a rectangle is 7 times its width. If its perimeter is 120 cm, what is the... (answered by scott8148)
The rectangle shown has a perimeter of 46 cm and the given area. Its length is 7 more... (answered by josgarithmetic)
The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle (answered by ewatrrr)